+ 1
Explain !! Plss😅
https://code.sololearn.com/cHB2k2JYbTqh/?ref=app input 8 1 3 8 2 9 7 6 5 expect output 1 2 3 5 6 7 8 9 my output 1 2 3 8 9 why!!!!
2 Respostas
+ 4
#include <stdio.h>
#define MAX 1000 // <-- This is unused why?
int main()
{
int i,n,temp=0,j;
// Array declaration doesn't belong here
// because we haven't got value for (n)
// int a[n];// <-- Wrong place for this...
scanf("%d",&n);
// Now that we have a value for (n) we can
// declare our array here...
int a[n];// <-- Right place for this...
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
for(j=0;j<n;j++)
{
for(i=0;i<n-1;i++)
{
if(a[i]>a[i+1])
{
temp=a[i];
a[i]=a[i+1];
a[i+1]=temp;
}
else
continue;
}
}
for(i=0;i<n;i++)
{
printf("%d ",a[i]);
}
return 0;
}
Please try to indent your code more accordingly, it improves readability and helps finding problem.
Happy coding ; )
+ 1
thanks alot man!! best community ever!!☺