someone can help me to carry out a program of binary to hexadecimal are basic form arrangements I am new to this

Question

estudio

Answer 1

Each 4 bits of a byte(reading from the right) creates a digit of a hexadecimal character.

Answer 2

but I do not know how to divide every four bits

Answer 3

You can parse binary strings to decimal

int number = Integer.parseInt("101010", 2);
String hexadecimal = Integer.toString(number, 16);
System.out.println(hexadecimal );

Prints "2a"

Answer 4

It does not come out, it marks me wrong. but thanks brother

Answer 5

divide binary number into groups of 4 bits, each group of 4 digits can have a possible value of between “0000” (0) and “1111” ( 8+4+2+1 = 15 ) giving a total of 16 different number combinations from 0 to 15.
The numbers 0 to 9 are still decimals, but the numbers from 10 to 15 are represented by capital letters of the alphabet from A to F

bin = 0011;
while (bin > 0) {
rem = bin % 2;
dec = dec + rem * i;
i = i * 2;
bin = bin / 10;
}
i = 0;
while (dec != 0) {
hex[i] = dec % 16;
dec = dec / 16;
i++;
}

for (j = i - 1; j >= 0; j--)
{
if (hex[j] > 9)
System.out.print((char)(hex[j] + 55)+"\n");
else
System.out.print(hex[j]+"\n");
}