number and square in c

Question

Write a program to display the following output using for loop,
1 1 2 4 3 9 4 16……..10 100.

Answer 1

for(i=1;i<limit; i++){

int result = i*i;
printf(" %d ", result);
}

Answer 2

Just for those who want it in one line :
for(int i = 1; i < 11; printf("%d %d ", i, i*i), ++i);

Answer 3

#include <stdio.h>

int print_square(int n) {
int s=1;
if(n < s)
return -1;
else
for(;s <= n; s++)
printf("%d %d ", s, s * s);

return 0;
}

int main(int argc, int** argv) {
int n;
printf("Input : "), scanf("%d", &n);
return print_square(n);
}

------- execute ------
Input : 10

1 1 2 4 3 9 4 16 5 25 6 36 7 49 8 64 9 81 10 100

Answer 4

1) In case you have specified number of digits needed and all you need is output, not storing values.
for ( i=1; i=<n; i++)
printf("%d", i*i);
2) In case you need this values stored, i would recommend using an array and later manipulating with Array data (you can sort it, delete elements, add new, modify etc)
int array[] ;
for ( i=1; i=<n; i++)
array[i-1] = i*i;
//printing array
for (i=0; i<n; i++)
printf("%d", array[i]);