How I can put output from rand() to X?

Question

I want to make sorta Horoscope but I don't know how to write rand() output into x. How can I do it?

Answer 1

i think this is what you wanted
https://code.sololearn.com/c5L06rLs94SD/?ref=app

Answer 2

Sreejith it really doesn't.
0 refers to integral value while null refers to unknown which means that we don't know the value.

Answer 3

Sreejith yeah! It's what I needed. lol I dumb cus not tried this

Answer 4

x = rand()
is that what you wanted??

Answer 5

I tried do it. It's not working

Answer 6

show your code

Answer 7

I can't do it rn. Maybe later ok?

Answer 8

sure

Answer 9

auto x = std::rand();

make sure to set:
srand(time(nullptr))

also, I wouldn't recommend to use std::rand(), use the random header instead.

std::random_device rd;
std::mt19937 gen(rd());
auto x = gen();

Answer 10

I using srand(time(0));

Answer 11

0 is not null.
(void*)0 is null not nullptr.

Answer 12

does the same thing
it won't matter

Answer 13

#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;

int main() {

srand(time(0));

int x = rand();

}

Answer 14

ReimarPB it's don't work for me.

Answer 15

BuddyValera are you outputing the value ?

Answer 16

Yeah

Answer 17

Cain Eviatar here is my code:
#include "stdafx.h"
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;

void Aries() {
srand(time(0));

int f = rand();

int c;

cin » c;
if (c == 1) {

for (int x = 1; x < 2; x++) {
cout « "\nYour lucky number is: " « 1 + (rand() % 10) « endl;

}
if (f == 4) {
cout « "Hi";
}
}
}

int main() {
Aries();

}

Answer 18

ReimarPB I also need to use it in if()

Answer 19

inside for loop

f=1+(rand()%10)
cout <<"\nYour lucky number is: "<< f << endl;

edit: you don't need the loop, remove the for loop

Answer 20

BuddyValera oh I didn't know you wanted to output it

Just add "cout >> x;" to the code I made above