Write a program to reverse print from 15 to 1?

Question

plz try this program

Answer 1

Python code:

l = []
l.extend(range(1,16))
print(l[::-1])

Answer 2

plz give the answer in c++ and using class and object

Answer 3

#include <iostream> // std::cout
#include <algorithm> // std::reverse
#include <vector> // std::vector

int main () {

std::vector<int> myvector; // set some values:

for (int i=1; i<10; ++i) myvector.push_back(i); // 1 2 3 4 5 6 7 8 9

std::reverse(myvector.begin(),myvector.end()); // 9 8 7 6 5 4 3 2 1 // print out content:

std::cout << "myvector contains:"; for (std::vector<int>::iterator it=myvector.begin(); it!=myvector.end(); ++it) std::cout << ' ' << *it;

std::cout << '\n'; return 0;
}

Answer 4

#include<stdio.h> #include<conio.h>

void main() {

int n;
clrscr();

printf("\n"); //for new line

// While Loop

n=15; //Initialize while(n>=1) // Condition
{

printf(" %d",n);

n--; // Decrement

} getch(); }