Changing the value of hex (help)

Question

I want to output the hex value of number 1 to 5 using a loop but then the hex is not changing it is still 22ff1c

Output target:

hex of num=0 is 22ff1c
hex of num=1 is 22ff18
hex of num=2 is 22ff14

and so on..

Here is my code:

#include <stdio.h>
int main() {
int num = 1;
while(num <= 5) {
printf("hex of num=%d is %x\n", num, &num);
num++;
}
}

Answer 1

Just pass the <num> as the second argument to printf, currently you are passing the address of the <num> variable (cmiiw)

printf("hex of num=%d is %x\n", num, num);

Hth, cmiiw