Pointer Issues

Question

#include <iostream>
using namespace std;

int x = 5;
int *p = &x;

int main()
{
*p++;
cout << *p;
return 7;
}
Whenever I run the above code I get this

Output
4947972.
I'd have thought since I pointed to 'int x' that the increment would cause an increment in x certainly not this integer I'm getting.
Why 4947972 & not 6.

Answer 1

edit as int *p=&x;

Answer 2

I have seen a similar case a while ago, as I recall the solution was to use parentheses to the increment statement, so to lift the precedence, unfortunately I couldn't find that thread, and I can't explain it as good as they did there, anyways it goes like:

(*p)++;

With pre-increment it is:

++*p;

Hth, cmiiw

Answer 3

My bad, I skipped that in the description....
But yeah it was already 'int *p = &x;' in my code

Answer 4

I'm guessing it has to do with the increment of '*p' changing the address '*p' points to, don't know if this makes sense but I just don't wanna keep guessing.