Java - Fix errors

Question

public class MathUtils {
public static double average(int a, int b) {
return a + b / 2;
}

public static void main(String[] args) {
System.out.println(average(2,1));
}
}

Answer 1

It is returning 2.0.

Answer 2

a=> int value.
2=> int value
b=>int value
a+b/2according your expression first of all opreator order is / , +
so first b/2 int / int take place.1/2=>0
now a+0 => 2+0=2
now it's return double
so 2.0 print...
for how to resolve it see
Hatsy Rei comment....

Answer 3

replace line
return a + b / 2;

with
return (double)(a + b) / 2;

Answer 4

public class MathUtils {
public static double average(int a, int b) {
return (a + b) / 2.0;
}

public static void main(String[] args) {
System.out.println(average(2,1));
}
}

Answer 5

return (a + b) / 2.0;

Answer 6

return (a / 2.0 + b / 2.0);

Answer 7

public class MathUtils {
public static double average(int a, int b) {
return (a + b) / 2.0;
}

public static void main(String[] args) {
System.out.println(average(2,1));
}
}

Answer 8

public class MathUtils {
public static double average(int a, int b) {
return (a + b) / 2.0;
}

public static void main(String[] args) {
System.out.println(average(2,1));
}
}