ANSWER PLZ

Question

Fill in the blanks to create a pattern that matches strings that contain 3 characters, out of which the last character is an exclamation mark.
r"___

Answer 1

(\n|.){2}\!$

Answer 2

import re

num = "07987549836"
pattern = r"9"
num = re.sub(pattern, "0", num)
print(num)

Answer 3

the ans of this Q's is :- ..!

Answer 4

Question :-
Why "..!" ?
I don't understand

solution:-
The question is says about three letters and last one is ! so " ..!"

Two dots for first two letters.

Answer 5

The answer is
x = str. replace ('!', '.')

Answer 6

Please, don't help them ValentinHacker, it won't help them

Answer 7

..!

Answer 8

..!

Answer 9

Ans :
re"..!quot;

Answer 10

..!

Answer 11

..!

Answer 12

The blanks is ..!

Answer 13

the answer is ..!

Answer 14

Ans:
r"..! quot;

Answer 15

r"..! quot;

Answer 16

Why "..!" ?
I don't understand