What is returned as a result of calling makeFancy("JAVA")?

Question

public static String makeFancy(String s) {

if (s.length() == 0) {

return "*";

}

return "*" + s.substring(0,1) + makeFancy(s.substring(0, s.length()-1));

}

options are:

1)*J*A*V*A

2) * *J*A*V*A* *

3) *J*J*J*J*

4) *A*A*A*A*

5) *JJJJ*

Answer 1

https://code.sololearn.com/cH4l0XU20R1L/?ref=app
option 3::as you want answer not explanations:::

Answer 2

vishal patil spamming in your own questions will only make it less likely for it to be answered

also why don't you just test the code yourself lmao you have the code with you

Answer 3

CAN SOMEONE PLEASE TELL ME THE ANSWER WITHIN TWO HOURS I WOULD BE GREATFULL FOR YOUR HELP

THANKYOU

Answer 4

HELP ME PLEASE

Answer 5

SOMEBODY PLEASE

Answer 6

please tell me its my assigment question and i dont know how to put the code its coming error every time so please tell me i beg for the answer