Can someone pls explain the output of this snippet

Question

int x=0; for (int z=0; z<5; z++) { if((z>3) && (++x>2)) { x+=7 } } System.out.print(x);

Answer 1

its printing out x
the loop runs 5 times, so 5 times those things happen
1. z > 3?
2. x =x+1
3. x>2?
4. if 1. and 3. are true
x is made 7 bigger.

if you want to know the output, just use it in the playground.

Answer 2

bro I know the output it's 2....that's where I'm stuck.. nd not getting how 2 could be the output

Answer 3

I considered the loop and also can't see how the result could be 2.

It starts by saying...
x = 0
And the loop says...
z = 0
Since z < 5, the loop runs, but inside the loop it asks if z > 3, which is false so the 7 is NOT added. But, by also saying ++x>2, it incremented x by one. So now...
x = 1
Now, the next stage of the loops occurs. z is incremented by z++ in the loop paratheses.
z = 1
Then same thing happens this time. The 7 isn't added, but x is increment by 1.
x = 2
The next loop runs and z is incremented.
z = 3
The if statement still isn't satisfied since z>3 is false (it is equal). x is incremented on the if statement to 3 again.
x = 3
Now when the loop runs, z is incremented.
z = 4
The if statement increments x.
x = 4
Both conditions are true so the 7 is added.
x = 11
The loop tries to run again but now, z is incremented...
z = 5
And the loop stops since z<5 is false.

I think the output should be 11.

I just ran it and the output was 1. Now I am very confused.

Answer 4

exactly bro I too approached in the same way and got the output as 11...but the compiler shows 2!!