Hello there!, Who can help me to know ? What do this %*c?I am working in C

Question

This is line of my code
scanf("%c%*c",&r);

Answer 1

Having a function:
void func(char *out) {
*out = 'a';
}

calling it with:
char f;
func(&f);

updates f = 'a' so yes you get a pointer to char.

Answer 2

Your scanf reads 2 characters. %c specifies read a character storing it in the r variable. The %*c specifies read a character and do not stored it.

Answer 3

Say your input is "a b":
char f,s;
scanf("%c%*c%c", &f, &s);
sets f = 'a'; s = 'b'; and the ' ' is tossed. You need to pass the addresses of f and s so scanf can write to them so &f gets the address of f.

Answer 4

thank you so much!

Answer 5

is second parameter is apointer to Char?
sorry, but in the book that I read some Codes use %*c, so I am lost, for example
prinntf("add ID studen"); scanf("%d%*c",&h.nal);

printf("curse");.
scanf("%d%*c",&a.curse);