int a=-1; cout<<(a++&&1);

Question

what is the output of this code? I need an explanation about this?

Answer 1

Jagadesh Ramesh, the other side is not zero. There is a postfic ++, this code increments a after calculating the expression in brackets. So it is actually (-1&&1), which is 1 (true), because all ints, except 0 are true.

And if we change this code to(++a&&1) this will be 0, because prefix ++ will first increment a, and then use the incremented value to calculate the expression.

Answer 2

Jagadesh Ramesh

in c++ for booleans

1 ( or any number other than 0) is true

0 is false

https://code.sololearn.com/cBhiuiXQRo53/?ref=app

Answer 3

Jagadesh Ramesh

well && operators check if true or false.

unless there is one or two false values it will be true.

Answer 4

thank you so much guys. I got it.

Answer 5

Output:
1

Answer 6

but using this && operator both the conditions should be satisfied right? one side is 1 that is okay. but other side may come zero. so how it returns 1.

Answer 7

can you please explain how it works