Palindromic queries

Question

What is the logical error in my program

#include<stdio.h>
#include<string.h>
int main()
{
char s[100001],temp[100001];
long long int t,i,j,flag=0,a,b,c,d,beg,end;
scanf("%s",s);
scanf("%ld",&t);
strcpy(temp,s);
if(t>=1 &&t<=333333 && strlen(s)>=1 && strlen(s)<=100001)
{
while(t--)
{
scanf("%lld%lld%lld%lld",&a,&b,&c,&d);
char ch=s[a-1];
s[a-1]=s[b-1];
s[b-1]=ch;puts(s);
beg=c-1;
end=d-1;
for(j=0;j<=(d-c)/2;j++)
{
if(s[beg]!=s[end])
{flag=1;break;}
beg++;end--;
}
if(flag==1)
printf("No\n");
else
printf("Yes\n");
strcpy(s,temp);
flag=0;
}
}
return 0;
}

Answer 1

#include<stdio.h>
#include<string.h>
int main(){
char s[100001],temp[100001];
long long int t,i,j,flag=0,a,b,c,d,beg,end;
scanf("%s",s);
scanf("%ld",&t);
strcpy(temp,s);
if(t>=1 &&t<=333333 && strlen(s)>=1 && strlen(s)<=100001){
while(t--){
scanf("%lld%lld%lld%lld",&a,&b,&c,&d);
char ch=s[a-1];
s[a-1]=s[b-1];
s[b-1]=ch;puts(s);
beg=c-1;
end=d-1;
for(j=0;j<=(d-c)/2;j++){
if(s[beg]!=s[end]){
flag=1;
break;
}
beg++;
end--;
}
if(flag==1){
printf("No\n");
}else{
printf("Yes\n");
strcpy(s,temp);
flag=0;
}
}
return 0;
}

now it should work I think

Answer 2

there are some { and } missing ...

but I don't understand what your code trys to do can you tell me/us