Python: Operand Error

Question

I get this error:

File "/storage/emulated/0/Test.py", line 14, in <module>
print ("is: "), ("num1" + "num2" + "num3" / 3)
TypeError: unsupported operand type(s) for /: 'str' and 'int'

When I run this program:
num1 = '90'
num2 = '87'
num3 = '82'

print ("The average of the following numbers: ")

print (num1)
print (num2)
print (num3)

print ("is: "), ("num1" + "num2" + "num3" / 3)

Any ideas? Been a while since I last programmed..

Thanks :)

Answer 1

This works:

num1 = 90
num2 = 87
num3 = 82

print("The average of the following numbers: )

print(num1)
print(num2)
print(num3)

print("is:", (num1 + num2 + num3) / 3)

https://code.sololearn.com/cVKjtQ9Su3lB/?ref=app

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Answer 2

First, you should not put variable names in quotes. Now you are concatenating name strings, get the string "num1num2num3" and are trying to delete it by 3 - and of course you can't.

But even if you'll remove the quotes in last line you'll still get the same error. Because you initialize variables with numbers in quotes - so you don't get number e.g. 90, but a string "90". So in the last line you get the string " 908782" and are trying to divide it by three.

Answer 3

A, hell, there's also a crazy print call with two brackets in a row. You can't call functions like this, never. All arguments should be inside one exterior brackets. You should do that like this

print("is: "+((num1+num2+num3)/3))

And, as you could have noticed, you should put sum in brackets, because otherwise you are adding num1, num2 and num3/3 and that, obviously is not what you want.

Answer 4

Will do that next time, my apologies! It's working great now, thanks! :)

Answer 5

Still getting the same error after removing those quotes, anyways thanks for the heads up! What else am I missing here? Thank you :)

Answer 6

Cool! I remember seeing those brackets, thanks! I recalled it now, but one last issue though, EOF parse error. Perhaps it is with the int problem?

Answer 7

Ah, yes, you cant just concatenate an int to string, that's not js You should do

print("is: "+str((num1+num2+num3)/3))

or

print("is:, end=" ");
print((num1+num2+num3)/3)

Answer 8

Nice, getting there. Now I have this program:
num1 = '90'
num2 = '87'
num3 = '82'

print ("The average of the following numbers: ")

print (num1)
print (num2)
print (num3)

print("is:, end=" ");

print ((num1+num2+num3)/3)

Then getting an error:

File "/storage/emulated/0/Test.py", line 14
print("is:, end=" ");
^

Thanks for the effort though :)