What coding i use for armstrong

Question

plzz tell me

Answer 1

Please show your attempts when asking for help, many thanks.

Answer 2

/*
you can copy and paste in your IDE
then run

you can also change variable 'number' to check if other numbers is Armstrong or no
*/

public class Armstrong {

public static void main(String[] args) {

int number = 1634, originalNumber, remainder, result = 0, n = 0;

originalNumber = number;

for (;originalNumber != 0; originalNumber /= 10, ++n);

originalNumber = number;

for (;originalNumber != 0; originalNumber /= 10)
{
remainder = originalNumber % 10;
result += Math.pow(remainder, n);
}

if(result == number)
System.out.println(number + " is an Armstrong number.");
else
System.out.println(number + " is not an Armstrong number.");
}
}