Tripple dollar. Please explain me, step by step, what does interpreeter do here and why it outputs dollardollar?

Question

code:

$dollar = "dollar";
$$dollar = $dollar."dollar";
$dollardollar = $dollar;
echo $$$dollar;

Answer 1

(I'm not sure if that kind of imaginary parentheses helps, but I'hope that such verbal step by step explanation is clear anyway... you just have to "parse and evaluate" those multiple "$" yourself like interpreter does.)

Answer 2

This is pretty self explanatory as it creates two strings of dollar joins them and the result is dollardollar

Answer 3

1st line: $dollar is equal to dollar.
2nd: see $$dollar as $($dollar), now put a value of $dollar instead of $dollar and you'll get $(dollar), now drop those parentheses;
now, $dollar equals concatenated $dollar (it's value, which is "dollar") and string literal "dollar". (So, now $dollar equals "dollardollar").
3rd: a new variable comes here, it's $dollardollar and it equals "dollardollar" too.
4th: You can imagine some parentheses here again for those variable variables. $($($dollar)). So, evaluate "first" "expression" here (inside parentheses). $dollar equals "dollardollar" and now we have $($(dollardollar)). Drop the pair of parentheses as we have already evaluated "expression" inside... $($dollardollar). Evaluate again. $dollardollar equals "dollardollar" so we have $(dollardollar). Drop the last pair of parentheses and you'll have last and long waited variable here: $dollardollar which value is "dollardollar" and echo $dollardollar outputs "dollardollar".

Answer 4

BroFarOps Please help this guy...!

Answer 5

Hi.
I manage to solve it out few days ago with my friend who works in IT and forgot about this question topic.
However this explanation is exactly what I requested for.
Thank you much for your effort.
Take care.
Greets.