Why it does not run?if i change to private: int n=68; it runs actually.

Question

#include <iostream>

using namespace std;

class MyClass
{
public :
MyClass();
void myPrint();
private:
int n;
n=69;
};

MyClass::MyClass() {
}
void MyClass::myPrint() {
cout <<n<<endl;
}

int main() {
MyClass obj;
obj.myPrint();
}

Answer 1

It's probably because n is declared and assigned on separate lines. Compiler doesn't know what to do with n=69; when it's outside a method.

Answer 2

Vivek Mishra kya bol raha hai bhaisab? mera MyClass () and void myPrint () methods are set in public already but the variable n is initialized in private .
this program doesnt run. however if i declare and initialized n in the same line as private,it runs. why?

Answer 3

BlazingMagpie exactly my thought. so we cant declare and initialized in different lines in this case.,eh??