Output of following expression of C programme

Question

int i=8,j=5;
float x=0.005,y=-0.01;
char c='c',d='d';
Expression is
(3×i-2×j)+(i%2*d-c)

Answer 1

Well, I just tested it in Code Playground, the result evaluates to -85, here I try to break the order of operation of the expression, I hope it is clear enough to understand : )

(3 * i - 2 * j) = (3 * 8 - 2 * 5) = (24 - 10) = 14

(i % 2 * d - c) = ((8 % 2) * 'd' - 'c') = (0 * 100 - 99) = -99

14 + (-99) = (14 - 99) = -85

Hth, cmiiw

Answer 2

Have you tried to execute it and get the answer by yourself?...
Then, if you don't get it, you can ask others to explain...

Answer 3

it's simple algebraic operations , you just need to know one thing apart from that : whenever you include a character in a arithmetic operation then the number that would be used for it would be it's ASCII code.

Answer 4

my answer was also -85. I just wanted to confirm cause I wasn't sure. thanks a lot .

Answer 5

why would I ask a question if I haven't done it myself

Answer 6

Please also explain the result

Answer 7

the result is 0.1199