Can you expalin this output?

Question

y=list(range(10))
def h(x):
if(x%2==0):
return x*5
else:
return False
print([i for i in y if h(i)])

#output = [2,4,6,8]
but why x is not multiply by 5 and where is 0 in the output list can anyone explain this.

Answer 1

Maninder Singh what made you think to add c++ in this question tag ? this is not applicable to c++

Answer 2

you prints i but not h(i).
you checks if h(i) is true, but 0*5 == 0 == false.

Answer 3

print([x * 5 for x in range(1, 10) if x % 2 == 0])
#will print [10, 20, 30, 40]

==

lst = []

for x in range(1, 10):
if x % 2 == 0:
x *= 5
lst.append(x)
print(lst)

#will print [10, 20, 30, 40]

==

y = list(range(10))

def h(x):
if x % 2 == 0:
x *= 5
return x

print([h(x) for x in y if x % 2 == 0])
#will print [0, 10, 20, 30, 40]