+ 2
Python3
code: x=1 y=1 if x and not y: print("a") else: print("b") I can't understand why the solution is "b".
11 Respostas
+ 3
in a Boolean context 1 converts to True, and not y converts to False
True AND False is False, so we execute the else branch, not the 'if'
+ 2
0 = false 1 = true. since x and y are both 1(or true) saying ânot yâ returns the opposite of true(false)
if statements only run if the value is true.
else runs if no if / elif statements run.
therefore, b is printed
0
The if statement is passed if the evaluated condition gives you True. As it was explained, 1 and not 0 will lead to False.
For better understanding, you should test and see how python evaluates different types of values. For instance, any 'int' or 'float' value which is different than 0 will evaluate to True, while the 0 value will lead to False. An empty string, "", will evaluate to False, and a string with one or more characters will evaluate to True. An empty list will evaluate to False, and a list with one or more items will evaluate to True. Etc.
In the if condition above, x is evaluated to True and y to True. Thus, you get the expression:
if True and not True:
...
Finally, it will lead to False, because it's the AND result between True and False (not True).
I hope that was helpful! :) Happy coding!
0
If not(x and y):
0
Python3
code:
x=1
y=1
if x and not y:
print("a")
else:
print("b")
I can't understand why the solution
is "b".
0
ok, its got to do with booleans.
True=1
False=0
b is true.
not(b) means opposite of true, so not b is false.
if a and not b is a false statement. if not b was true then itâd be a true statement.
hope you understood.
0
In a Boolean 1 means true and 0 means false, and X and y are 1 here so both true. The if statement asks if X is true and y is false, that isn't the case so it executes the else and prints b
0
If u want to make the solution 'a' use 'or' at the place of 'and'.
- 1
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