+ 1
can somebody explain this code to me?
function func($arg) { $result = 0; for($i=0; $i<$arg; $i++) { $result = $result + $i; } return $result; } echo func(5);
2 Respostas
+ 2
This is a function will execute for 5 times as you see on the statement echo func(5).
Hence $i the first time is 0, $i is minor to $arg, you have to cout forward.
Return to this operation 5 times($result=$result+$i)
$i for the 2th time become 1,
3th=2,
4th=3,
5th=4 add to the $result,
1th=0,
2th=1,
3th=3,
4th=6
then $i for fitfh time become 4 add to the forth $result= 6.ok?
5th time the $result is 10.
I hope as this may help you