Why does my code return "time limit exceeded"

Question

Write a function, investment(PMT, n, i) that calculates a customer's savings at some point in the future, if:
• an amount is invested at the End of every year, starting with amount of PMT at the end of this year,
• at an interest rate of i% per year, compounded annually,
• the investment doubles every second year(cumulatively).

###START FUNCTION
def investment(PMT, n, i):

# YOUR CODE HERE

return round(investment_balance, 2)

###END FUNCTION.

investment (15000, 30, 0.1045) == 1954935238.47

https://code.sololearn.com/c3zpUsmMrm2c/?ref=app
https://code.sololearn.com/c3zpUsmMrm2c/?ref=app

Answer 1

I have given it a try, the code works but the calculation is somewhat wrong:
def investment(PMT, n, i):
x = 0
investment_balance = PMT

while x < n:
if x % 2 == 1:
investment_balance *= 2

investment_balance *= (1+i/100)
investment_balance += PMT
x += 1
return float(round(investment_balance, 2))
print(investment(15000, 30, 0.1045))

Answer 2

lYou increase x only if x % 2 = 1.

It will never happen, your code loops forever.

Answer 3

Not forgetting to thank Paul Jacobs for breaking it down for me and correcting me where i was wrong. You the best Paul🎖

Answer 4

What would you suggest i do to get an output 1954935238.47 given the arguments

Answer 5

The code you just provided run fine yes, i just wonder why does it output such a low value though.

Answer 6

Thanks Ina it returned a more reasonable value, abit more than it should but close enough to be accepted. Thank you so much🏆😊