I want to build a simple program. Please tell me if it is correct b coz i am not getting the results.......

Question

x=input("Enter a number between 1 to 3")
if x==1:
print("You typed number one")
elif x==2:
print("You typed number two")
else:
print("You typed number three")

This is the code. I wan the input to compare with the if condition and just print the result. Please tell me where I am wrong

Answer 1

the input from the user is a string - u need to convert it into an integer to work

try
x=int(input("Enter a number between 1 to 3"))

Answer 2

Yes, it works!!! Thanks a lot Eitan Stein!

Answer 3

Here is my code:

x = -1 # -1 to be sure that you enter the while block code cause it is not in the range of 1 and 3.

successful = (x in range(1, 4))

while successful == False:
x = input("Please enter a number between 1 and 3: ")
successful = (x in range(1, 4))

print "You typed: %s" %(x)