how does sum is calculated in this

Question

int arr[] = {11, 35, 62, 555, 989};
int sum = 0;

for (int x = 0; x < 5; x++) {
sum += arr[x];
}

cout << sum << endl;

Answer 1

//1st iteration
x = 0, 0 < 5 (true)
sum += arr[x] --> 0 += 11
sum = 11
increments x --> x = 1

//2nd iteration
x = 1, 1 < 5 (true)
sum += arr[x] --> 11 += 35
sum = 46
increments x --> x = 2

//3rd iteration
x = 2, 2 < 5 (true)
sum += arr[x] --> 46 += 62
sum = 108
increments x --> x = 3

//4th iteration
x = 3, 3 < 5 (true)
sum += arr[x] --> 108 += 555
sum = 663
increments x --> x = 4

//5th iteration
x = 4, 4 < 5 (true)
sum += arr[x] --> 663 += 989
sum = 1652
increments x --> x = 5

//6th iteration
x = 5, 5 < 5 (false)
terminates loop

sum = 1652

Answer 2

Explanation of something similar, hope it helps: https://www.sololearn.com/Discuss/400109/?ref=app

Answer 3

your welcome

Answer 4

thanks ahmad

Answer 5

Thorught the "for" loop that add all "arr" items to sum (inited to 0 at start)

Answer 6

although it helped in understanduling the concept but the link u provided is for java