How to draw X shape using *

Question

I tried this code but only works when num=5:

void draw_X_Shape(int n)
{
int i,j;
for(i=0;i<5;i++)
{
for(j=0;j<5;j++)
{
if((i==j) || (i+j)==(n-1))
{
printf("*");
}
else
printf(" ");
}
printf("\n");
}
}
int main()
{
int num=5;
draw_X_Shape(num);
return 0;
}

Answer 1

Try it like this:

void draw_X_Shape(int n)
{
int i,j;
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if((i==j) || (i+j)==(n-1))
{
printf("*");
}
else
printf(" ");
}
printf("\n");
}
}
int main()
{
int num=7;
draw_X_Shape(num);
return 0;
}

I have changed the '5' in the lines that start with for into 'n'.

Answer 2

Thanks Paul Jacobs

Answer 3

but if n is even then x is not look like x

Answer 4

iqtiza hasan yes u r right, did you try how to solve this?

Answer 5

public static void Main(string[] args)
{

int n=5;
for (int i =0;i<n;i++){
for(int j=0;j<n;j++){

if (j==i||(n-j)==i){

Console.Writeline("*");

}
else
{

Console.Writeline(" ");

}
}
}
Console.Writeline("");
}
}

Probably the simplest way i could have think of ..