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Is there any way to pass in multiple conditions for a while loop without using a nested if statement? (see lines 31 to 36)
10 Respostas
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while m[:-4:-1][::-1] not in (user, cpu):
m.append(randint(0, 1))
wins += m[:-4:-1][::-1] == cpu
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Maybe
while True:
if m[:-4:-1][::-1] in [user, cpu]:
wins += m[:-4:-1][::-1] == cpu
break
m.append(randint(0, 1))
I can't test it because code playground seems to be down again
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yes you can, using and
while condA and condB
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correct me if im wrong
but you need to break the loop if the condition are true right ? did you change == to != ?
while m[:-4:-1][::-1] != user or m[:-4:-1][::-1] != cpu:
if m[:-4:-1][::-1] == cpu:
wins += 1
break
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Mert Yazici That worked!! Thanks a lot
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Anna That works! How did this not occur to me! Anyway thanks a lot!!
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It doesn't change a whole lot, but could you connect your two ifs with or? Then you have only one break case...
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HonFu That is what I did earlier. But I changed it just to increment the wins counter in lesser number of lines. Thanks for the input thoughđđ
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but that doesn't work for me as I need to use or.
Even then, that syntax doesn't work
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Taste You are right. For the conditions on the while loop, I do have to use !=. But for me two. conditions in the while loop makes it an infinite loop. that never matches a condition.