Please help

Question

how to make a code with testcase like
input : 4a 3c 9o 0
output : aaaacccooooooooo0

input : 11b 3k 9
output : bbbbbbbbbbbkkk9

Answer 1

def get_part(input):
if len(input) <= 1:
return input
num=int(input.split(input[-1],2)[0])
return num*input[-1]

def get_line(input):
parts=[]
for i in input.split(" "):
parts.append(get_part(i))
return " ".join(parts)

inputs=[]
inputs.append("4a 3c 9o 0")
inputs.append("11b 3k 9")
for input in inputs:
print(get_line(input))

Answer 2

your answer is rightt i just replace it with new variable with input. thankyou so muchhh gbu

Answer 3

@DFX but if i input 8dad 7a. the output just dddddddd aaaaaaa. how to have the output is daddaddaddaddaddaddaddad aaaaaaa

Answer 4

@Alex: Ah, I did not except that input because it differs from the examples. In that case, I would use a regular expression to get the nuber part from the beginning. If there is no number part or there is only number part, then let's just print it.

import re

def get_part(input):
m = re.search('''^([1-9][0-9]*)([^1-9].*)#x27;'',input)
if m is not None:
return (int(m.group(1)),m.group(2))
return (1,input)

def get_line(input):
parts=[]
for i in input.split(" "):
(count,str)=get_part(i)
parts.append(str*count)
return " ".join(parts)

inputs=[]
inputs.append("4a 3c 9o 0")
inputs.append("11b 3keke 9")
inputs.append("2b0ss 3keke x")
inputs.append("l77t is 2n33t")

for input in inputs:
print(get_line(input))

Answer 5

multiply it by calculator