Why the pointer increases by 4 when the increment operator is used (ptr++)? Why there's something to do with int?

Question

int a[5] = {22, 33, 44, 55, 66};
int *ptr = NULL;

ptr = a; /* point to the first array element */
printf("%d %x\n", *ptr, ptr); /* 22 */
ptr++;
printf("%d %x\n", *ptr, ptr); /* 33 */
ptr += 3;
printf("%d %x\n", *ptr, ptr); /* 66 */
ptr--;
printf("%d %x\n", *ptr, ptr); /* 55 */
ptr -= 2;
printf("%d %x\n", *ptr, ptr); /* 33 */

Answer 1

Yes

https://overiq.com/c-programming-101/pointer-arithmetic-in-c/

https://codeforwin.org/2017/10/c-pointer-arithmetic.html

Answer 2

That's because sizeof(int) = 4. So pointer watches the next int. Pointer to double increments by 8, in order to point to the next double.