Python list

Question

b = 5
list=“”
while b<11:
b = b + 2;
if b%2 == 1
list=str(b)+” “ + list
print (list)

Please show me how to get to the output in steps. Thank you.

Answer 1

https://code.sololearn.com/cGtblssei0tm/?ref=app

Answer 2

b = 5 # Sets Value of b to Integer 5

list=“” # Creates an emty String

while b < 11: # This Loop will continue as long as the value b is smaller than 11
b = b + 2 # Adds 2 to b. With the first Iteration b is 7
if b % 2 == 1 # Checks if b is an odd Number
list = str(b) + ” “ + list # Adds the current Value of b to the List if the Condition of the if-Statement is True

print (list) # Output of the final List

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By the Way this Program makes not much sence. It starts with an odd number and adds 2 - it is logical that this must be an odd Number, too.

Answer 3

Because you add str(b) + list. If you want an ascending Order write

list = list + " " + str(b)

Answer 4

You can do it with a list comprehension

print([b for b in range(7, 13, 2) if b%2])

Answer 5

Python will execute your Code exactly in the Order you write it down:

list = list + str(b)

means that 'b' will be appended to the existing 'list'. The result is a 'list' in ascending Order.

list = str(b) + list

means that the existing 'list' will be appended to 'b'. The Result is a List in descending Order.

Answer 6

list is the Name of the Stirng you defined in Line 2.

Answer 7

You should define a List like that:
list = []
and add Items with
list.append()

https://www.sololearn.com/learn/JUMP_LINK__&&__Python__&&__JUMP_LINK/2431/
https://code.sololearn.com/cdPALq4G3C2N/?ref=app

Answer 8

I know the answer. I just need to know the steps to it.

Answer 9

Because I don’t understand how the output is the output

Answer 10

Please show me steps to it.

Answer 11

@Sebastian KeBler
Thank you so much. But I’m confused about how it’s 11 9 7 and not 7 9 11. Why is it in reverse?

Answer 12

So does it mean that “list” is nothing?

Answer 13

What is list? I don’t know the value for list.