Intersection array from two arrays, Java.

Question

Hi,

please could you look at this code, I would like to fill up an empty array of Int appending to it only the common elements from the two first arrays.
I am only using java.util.Arrays library, don't want to use any lists or hashset or whatever...just plain for loops and methods for arrays of Int.
Could you help me to complete the code?

public class Main3 {

public static void main(String[] args) {
int[] arr1 = {4, 23, 17, 2};
int[] arr2 = {23, 5, 17, 1};
int count=0;
for (int i = 0; i < arr.length; i++) {
for (int j = 0; j < arr2.length; j++) {
if (list[i] == list1[j]) {
count++;
int[] common = new int[count];
for (int k = 0; k < common.length; k++) {
common[k] = list[i];
}
}
}
}
}

of course the result is not that I was expecting...:( please help, thanks!

Answer 1

The code is modified. (https://code.sololearn.com/cvi3k6mqfm12/#java)
Check again.

I used a temp array before adding in common.

Answer 2

Many thanks Prokopios!

Answer 3

There are some errors in your code

1.
for (int i = 0; i < arr.length; i++) {
===>
for (int i = 0; i < arr1.length; i++) {

2.
if (list[i] == list1[j]) {
==>
if (arr1[i] == arr2[j]) {

3. common[k] = list[i];
==>
common[k] = arr1[i];

4. Add one more } at the end

Nevertheless the problem still exists. Numbers are duplicated in the array.
I believe that you want the distincts.

https://code.sololearn.com/cvi3k6mqfm12/#java

Keep in mind that in the above code I use 4 positions as a size of common array.
but I print only the common elements.

Answer 4

Thank you, I watched your code, but the output I was having in mind is an array, not single elements printed out.
Output should be something like:

common[] = {23, 17}

I was thinking of somehting like:

System.out.println(Arrays.toString(common[l]));

but it doesn't work even if I import java.util.Arrays :((