I wanna add second array to end of the first array.Can someone recover this code?

Question

#include<stdio.h>

char gift (char *sPtr1,char *sPtr2) {
int i=0,k=0;

while(sPtr1[i]!=NULL) {
i++;
}
for(; sPtr2[k]=NULL; k++){
sPtr1[i+k+1]=sPtr2[k];
}

}
int main() {

char string1[]="You can";
char string2[]=" go";

puts(string1);
puts(string2);

gift(string1,string2);

printf("%s",string1);

return 0;
}

Answer 1

You can't modify the original strings. You must allocate a new storage location for the string.
https://code.sololearn.com/cJ707PL3E108

Note: NULL is a pointer not a character so shouldn't be used in your code.

Answer 2

Thank you sir. I just don't know what is the mission of malloc at here . Could you explain for me ?

Answer 3

It allocates heap memory for your pointer to store the string (same as new in C++.) Normally, you would call free to return the memory, when done. But, your program exiting makes it unneccessary.

Answer 4

Thank you again for your help sir. Have a good day :))

Answer 5

posted comment in the code java