functional programming

Question

'''please explain how it works'''
#FUNCTIONAL PROGRAMMING
def apply_twice(func,arg):
return func(func(arg))

def add_five(x):
return x+6

print(apply_twice(add_five,10))

Answer 1

add_five(x) adds 6 (!?) to x and returns the sum.

test: print(add_five(4)) # output: 10

apply_twice takes two arguments, func and arg and then returns func(func(arg)).

If you call apply_twice with the arguments add_five and 10, this is what happens in apply_twice:

return func(func(arg)) => this is the same as return add_five(add_five(10)).

=> add_five(10) is 16.

=> add_five(add_five(10)) equals add_five(16).

=> add_five(16) is 22 and that's the return value of the function.

Answer 2

Thanks