So, in this code did the address of pointer k become -5?

Question

#include <stdio.h>
void func(int* x){
x-=5;
}
int main() {
int k=7;
func(&k);
printf("%d",k);
return 0;
}

Answer 1

Nothing really happens. x in func had the address of k and then contains the address of 5 bytes before that. However, you never use it so it doesn't have any lasting effect as x's value is a local and not returned.

Answer 2

John Wells doesn't x have 5 bytes * sizeof(int) value in func ?

Answer 3

func() was not return int or pointer.
first:void must be -> int or returnable value.
second: func(){... return x;}
third: k=func(&k)
and then you take response from program.

Answer 4

Baptiste E. Prunier yes, I forgot to look at the type of x so likely 20 bytes before k.