Why this code prints 44 ?

Question

#include <stdio.h>

int main() {
unsigned char x = 300;
printf ("%d", x);
return 0;
}

Answer 1

unsigned char is between [0, 255]
300 is bigger than 255 so it throws away extra bits and you get 300 % 256 = 44

Answer 2

unsigned char are 1 byte (8 bits) long...
But to represent 300 9 bits are needed, so there is no room in x for the 9th bit

If you use binary or hexa:

300 is: 1 0010 1100 12C

When assigned to unsigned char bit 8 (9th bit) is discarded, so:

x = 0010 1100 2C

2*16 + 12 = 44

:)

Answer 3

good answer diego Code