Nonlocal Keyward Error, how to solve?

Question

def myfunc1():
x = "John"
def myfunc2():
nonlocal x
x = "hello"
myfunc2()
return x

Answer 1

Levon Yeghiazaryan, which python version do you use?

Answer 2

Levon Yeghiazaryan Yes, that explains a lot 😏 Nonlocal will only work with python 3

Answer 3

Try running your code in the Code Playground. It works fine for me.

Answer 4

2.7, I guess the reason of your question.)

Answer 5

Thank you, I will do.

Answer 6

It works normally for me, it returns 'hello' when called. It doesn't raise any error.

Answer 7

It raises invalid syntax on nonlocal x