Java help

Question

public class Program
{
public static void main(String[] args) {
System.out.println(l(244));
}
static int l(int x ){
int sum=0;
while(x!=0){
sum=sum+(x%10);
x=x/10;
}
return sum;
}
}
I have code like this, but I don't know how to find sum only Even digits of some number

Answer 1

This should work too:
sum += ((x%10)%2==0? x%10: 0);

Answer 2

Sum of even digits or digits on even positions in number?
What should be the output of your sample input number(244)?

Answer 3

If I understood you, better use streams for such things and filter it how you want. Just an ex.:
int sum = IntStream.range(1, 245).
filter(x -> x % 2 == 0).
sum();

Answer 4

Thanks you so much