Int A={1,2,3} int n=sizeof(A) /sizeof( A[0] ) ;

Question

I want explanation for above code
Please explain it.

Answer 1

Here, you have an array of integers (A). The size of of the array is equal to the size of an integer times the length of the array.
So, sizeof(A) = sizeof(int) * 3 = 4 * 3 = 12
The size of the first element of the array (A[0]) is equal to the size of an integer.
So sizeof(A[0]) = sizeof(int) = 4

sizeof(A) / sizeof(A[0]) = 12 / 4 = 3

//All assuming the size of an integer is 4 bytes

Answer 2

Since int has 4bits.
Thus I have an integer array which has 3 elements of integer type, thus:-
3(number of elements in array)*4 (size of one int variable)= 12
Now, A [0] has size equivalent to 4 bits, Thus

12/4 (size of A [0])= 3

I hope u got it