How to print the following pattern in python.

Question

0
22
444
8888

Answer 1

c = 1
i = 1
print(i-1)
while i < 8:
c += 1
i *= 2
print(str(i)*c)

#Or, to make it 6 lines like Jay Matthews' solution ;)
c = [1,1]
print(c[0]-1)
while c[1] < 8:
c[0] += 1
c[1] *= 2
print(str(c[1])*c[0])

Answer 2

Oh, great. Thanks, Jay Matthews!
Got a shorter (5-liner) one, then:

c,i = 1,1
while i < 9:
print(str(i if i != 1 else i-1)*c)
c += 1
i *= 2

Answer 3

[print(str(2**i*(i>0))*(i+1)) for i in range(4)]