How does this work?

Question

int x,y;
x = 60;
y = x;
System.out.print("xd");
System.exit(x);
System.out.print(y);

Answer 1

So it works by initially printing the string “xd”

System.exit() with a non-zero parameter passed in then stops the currently running Java Virtual Machine stating something went wrong. (Zero passed as a parameter states behaviour is expected and I’m happy to terminate the program. Ref https://docs.oracle.com/javase/7/docs/api/java/lang/Runtime.html#exit(int) ) exit() takes an int argument so you are able to call exit(x), this just reflects you’re aborting the program in an unhappy state

System.out.print(y) is then not executed. If you take the exit() call out, your output is

xd60

Using println rather than print would give

xd
60