I want to ask that in c++ compiler why cout<<2*3+9 ; & cout<<2*3+9-1/2 ; giving me the same output "15" ??

Question

C++ Question

Answer 1

Hi Sandeep, I think this probably be how the expression was evaluated:

2*3+9-1/2 ;
(2*3)+9-(1/2) // <- integer division 1/2 yields zero
(2*3)+9-(0)
Output: 15

Hth, cmiiw

Answer 2

Oh yes .. got It . Thanks for helping me though 🙃