Why is ptr = a; shows error?

Question

int a[2][3] = { };
int *ptr;
int
a;

ptr = a;

printf("%d",*(ptr[2]+3));

Answer 1

The Pointer to an Array is always the Memory Adress of the first Element.

https://www.sololearn.com/learn/C/2962/

Answer 2

You must assign the memory address to ptr (= &a).

https://www.sololearn.com/learn/C/2933/

Answer 3

You have two variables named <a>, one is an int array ...
int a[2][3] = {};
and another one below an int
int a;

I'm not sure which of these you're pointing to with <ptr>, but from the printf call it seems you want to use the array, so remove that `int a;` from your code, and test again.

Answer 4

But array has its own pointer so why mention & ?

Answer 5

cause is that pointer must be following way

*ptr=a or else int *ptr=a