MultiDimensional Array

Question

/* kindly correct my program - print respective elements and their indexes also sum up them using loops?*/
#include <iostream>

using namespace std;

int main()
{
/*int arrTelNum[5]={3,5,7,9,11};
int sum=0;

for (int x=0; x<5; x++){
sum = sum+arrTelNum[x];
cout<<x<<" :"<<arrTelNum[x]<<endl;
}
cout<<"Total array indexes are: "<<arrTelNum[5]<<" and sum of values is: "<<sum<<endl; */
int array1[9]={2,4,5,-6,-8,9,-22,80,-45};
int arrSum1=0;
cout<<"Index"<<" : "<<"Array Element"<<endl;
for (int x=0; x<9; x++){
arrSum1 += array1[x];
cout<<x <<" : "<<array1[x]<<endl;
}
cout<<"Total number of indexes of first array are: "<<array1[9]<<endl;
cout<<" And sum of array elements of first array is: "<<arrSum1<<endl;
/*---------------------------------------------------------------------*/
/* Multidimesional Array */
int arrMulti2Dim [3][3]={{2,1,3},{3,4,5},{2,5,6}};
int i; int j;
int sumMulti2Dim =0;
cout<<"Element at index dimension 0x0 is: "<<arrMulti2Dim[0][0] <<endl;
cout<<"Element at index dimension 0x1 is: "<<arrMulti2Dim[0][1] <<endl;
cout<<"Element at index dimension 0x1 is: "<<arrMulti2Dim[0][2] <<endl;
cout<<"Element at index dimension 0x1 is: "<<arrMulti2Dim[1][0] <<endl;
cout<<"Element at index dimension 0x1 is: "<<arrMulti2Dim[1][1] <<endl;
cout<<"Element at index dimension 0x1 is: "<<arrMulti2Dim[1][2] <<endl;
cout<<"Element at index dimension 0x1 is: "<<arrMulti2Dim[2][0] <<endl;
cout<<"Element at index dimension 0x1 is: "<<arrMulti2Dim[2][1] <<endl;
cout<<"Element at index dimension 0x1 is: "<<arrMulti2Dim[2][2] <<endl;
cout<<"Index"<<" : "<<"Array Element"<<endl;
/*

for (i=0 && j=0; i<3 && j<3; i++ && j++){
arrMulti2Dim += arrMulti2Dim;
cout <<i , j<<" : "<<arrMulti2Dim[3][3]<<endl;

Answer 1

When you are displaying the number of indexes you refer to the non existing element. E.g. 'array1[9]', has 9 elements, so the last element should have index [8].

Answer 2

That's how you can print all of the elements on screen. It's for 3x3 array, but obviously if you change array size, you must change loop condition too.

int array[3][3];
for(int i = 0; i < 3; i++) {
for(int j = 0; j < 3; j++) {
cin >> array[i][j];
cout << array[i][j];
}
}

In this example the last element of an array is [2][2]. The first element always has index 0.

Answer 3

This is Solution : Don't forget to Upvote
...................................................

using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace SoloLearn
{
class Program
{
static void Main(string[] args)
{
int[,] num = { { 1, 2, 3 }, { 4, 5, 6 }, { 7, 8, 9 } };

//your code goes here
for(int i=0; i<3;i++)
{
for(int j=0;j<3;j++)
{

Console.WriteLine(num[i,j]);

}
}
}
}
}

Answer 4

Ok.
I want to know, how lements multidimensional arrays can be print on screen?
Please guide and help

Answer 5

Thanks for the help

Answer 6

And let me check on. I will come back to you. In case I have issue.