How many times will this loop run?

Question

for(int x=0; x=10; x++){}

Answer 1

infinite

Answer 2

Its like @Sakshi said.. there isnt a false condition

Answer 3

The value becomes 10 and does not increment after :/
Try this code in playground and see the output.
for(int x=0;x=10;x++){
cout<<x<<endl;
}

Answer 4

the answer is infinite only
first X=0 then X gets incremented and X becomes 10 but then also it will go on increasing because in the condition it is mentioned( X=10 )and not (X<10) or
( X >10 )or( X<=10)or (X>=10)

Answer 5

no no
it will check X=0
then inside the loop
see the incrementation X++
X increments up to 10 then it goes on incrementing because in condition it is not mentioned that X should be less than 10 or greater than 10 and the condition will never be false
see the condition again it's mentioned X=3 and not X==3 , that means X has been just assigned the value 3 , this will always evaluate to true and hence the loop will run for ever

Answer 6

thanks for the appreciation😊

Answer 7

re: @Sakshi, S!d (for later visitors)

int x = 9;
if(x=10) cout << "true" << endl;
else cout << "false" << endl;

output:
true

Get bitten by this error enough times and you'll develop an uncanny instinct for conditionals vs assignment.

Answer 8

thanks SakshiGupta you made my day. this was one new thing in c++ i learned from you.
i will follow you.

Answer 9

@S!d how?? condition is not true

Answer 10

@HashimNabreez how?? see the condition.

Answer 11

@DavidA your answer clicks to my mind.
thanks.
but i couldn't remember that error was an option in challenge.

Answer 12

@SakshiGupta loop will first initialize x=0 then will chek the condition which is x=10 which is not true. isn't the loop will be terminated at once??

Answer 13

3

Answer 14

Error. Condition is not boolean.