can someone explain this ? a[0]=3?

Question

int main()
{
int a[3]={1,2,3,};
for(int i=0;i<3;i++){
a[0]+=a[i];
}
cout<<a[0];
//Output 6
}

Answer 1

I would recommend taking a look at the supposed output...

(imho 4+3 is not 6, but what do I know)

Answer 2

Array a[3] is assigned 3 numbers: "1, 2, 3". => а=[1, 2, 3];
Further, using the cycle a[0] is assigned the sum of these numbers. => а=[7, 2, 3];
1. а[0]=1+1;
2. а[0]=2+2;
3. а[0]=4+3; // 7

Answer 3

Antonio Mariani stuff like that happens to me often enough too

Answer 4

Grigoriadis Georgios, Antonio Mariani
Explain to me how you managed to get the answer 6? 😂
👇
So
0: a[0]+a[0] //1+1;a[0]=2
1: a[0]+a[1] //2+2;a[0]=4
2: a[0]+a[2] //4+3;a[0]=6 ??? 😂

output: a[0]=6 ->output=6

Answer 5

Thanks for answers.