Chanllenge problem

Question

When I have a chanllenge in C++,a problem that I can't catch is that:
int x=2;
cout<<(x- ++ --x);
why the output is 0?
what is meaning of "-";

Answer 1

If x ++ will be collected
Int x = 5;
Int y = 10;
cout << ++ x + y;
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Int x = 5;
Int y = 10;
cout << x ++ + y;
If ++ x will ignore the variable because it is after x
But its x ++ values ​​will remain unchanged
But will display if you eject x again
Will collect 1 + x and thus the result will become {6}
In the other direction I did
count << x;
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I hope you understand my words and if you want to understand the more I have in the conversation

Answer 2

Ok,I get it,maybe I have never seen this usage before,haha.Thanks

Answer 3

Due to operator precedence. Answer will be zero

Answer 4

But there is operater precedence.

Answer 5

👍🤗

Answer 6

👍

Answer 7

I think it's equal to :
x - (++ (--x)) ;
So it's the same than x - x

Answer 8

But I think that operator is not vaild because between '-' and '++',there is no brackets,this is so confused

Answer 9

So are there compilers where the output can be different? Or code is always translated in the same way?

Answer 10

Thanks!