Coul someone explain this code to me? I don't understand why the output is 3.

Question

i=0;
cout<<(i=0 ? 1: 2 ? 3 : 4);
return 0;

Answer 1

a ? b : c; means: if a is true, return/evaluate b, otherwise return/evaluate c.

i = 0 sets i to 0 and returns 0 (false) (note that you're not using == for comparison, but = for assignment). So in the expression i = 0 ? 1 : 2, the second branch (2) is evaluated. You end up with 2 ? 3 : 4. 2 evaluates to true, that's why 3 is returned.

Answer 2

Every integer that is not 0 evaluates to true. 0 = false, everything else = true

Answer 3

clear doubt. Thank you

Answer 4

Thanks Anna, but why 2 does it evaluate as true?