Indentation error in break,can someone help.

Question

x=input()
print("ch")
if x==1:
print("ch1")
break
elif x==2:
print("ch2")

Answer 1

you use break in loops.

x=input()
print("ch")
if x=="1":
print("ch1")
elif x=="2":
print("ch2")

Answer 2

Break is more indented than print. That's verboten. It has to be on the same indentation level:

if x == 1:
print()
break

Answer 3

I guess you have used an extra space before the break statement and possibly before 3rd print statement. But I'm not sure.

Please re-indentate your code.✌🏼

Answer 4

Please upload your code to the code playground and post a link here

Answer 5

I tried that
But it's still not working

Answer 6

It's stil not working,did it run in yours?
If i'm keeping break in line with print then it's causing 'error break outside loop' and else it's causing indentation error

Answer 7

https://code.sololearn.com/cdhVkaN1HD4W/?ref=app

Answer 8

Choe thanks but i saw somehere on the internet they used break with if condition and it was running without any error,

Answer 9

https://www.sololearn.com/post/112583/?ref=app

Answer 10

Even in this app's tutorial they have used if with break.