How to take unlimited number of function arguments?

Question

--

Answer 1

def f(*args, **kwargs):
print(args)
print(kwargs)

f(1, 2, 'a', [], a=1, b=2, c=3)

Answer 2

Which language?

Answer 3

def fun(**kwargs):
print("kwargs")

# kwargs is keyword argument in which we give multiple arguments

Answer 4

Python

Answer 5

* is real gold. It also allows you to put iterables as a sequences of arguments.
func(*[1, 4, 27]) = func(1, 4, 27)