Java,How it works for loop

Question

isnt it like this, i = 7;7 < 49;--7
how it runs?
https://code.sololearn.com/cb72I9oUK6Ej/?ref=app

Answer 1

Rael

Well yes, but that is the case if you write it down like this
for(int i = 7;i < i*i;){
System.out.print(--i);
}
The --i in the loop is actually a single separate statement. If you break it down, it would be like this
for(int i = 7;i < i*i;){
System.out.print(i);
--i;
}
Therefore, changing it to i-- won't have any effect
nb. The third statement in for loop is executed after the code execution

Answer 2

~ swim ~
I think it's until the i reaches 1 not 0, because 1 < 1 is false

Answer 3

System.out.printf("i=%d i*i=%d\n", i, i*i);

i=7 i*i=49
i=6 i*i=36
i=5 i*i=25
i=4 i*i=16
i=3 i*i=9
i=2 i*i=4

Answer 4

result of --i and i-- is same value, but there is different behaviour when decrementing variable is assigned or used as parameter.

for(int i=7,ii=7; i< i*i; ){
System.out.printf("--i %d ii-- %d assigning\n", --i, ii--);
System.out.printf("%5d %5d after\n\n", i, ii );
}

--i 6 ii-- 7 assigning
6 6 after

--i 5 ii-- 6 assigning
5 5 after

--i 4 ii-- 5 assigning
4 4 after
...

Answer 5

~ swim ~
Agent_I
zemiak
Thank you!
One thing i dont understand is --i or i-- they both will output same in this code ,why?
isn't the --i will decrease 1 first before print it out?